Structures - Nodal Analysis Practice

Here is the question we did today:

First I took the bottom node to work out the internal forces in B and A.

I then took the middle node.  To build on last time's question this node now has a force acting on it and so C is not redundant.  Simultaneous equations are now required to solve the forces here.

Because we now know the force in D, we know that the reaction X in the wall is equal and opposite to it.

And finally looking at the bottom node we can work out the reaction Y.